3X^2+100x-15000=0

Solution for 3X^2+100x-15000=0 equation:

3X^2+100X-15000=0

a = 3; b = 100; c = -15000;
Δ = b2-4ac
Δ = 1002-4·3·(-15000)
Δ = 190000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{190000}=\sqrt{10000*19}=\sqrt{10000}*\sqrt{19}=100\sqrt{19}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-100\sqrt{19}}{2*3}=\frac{-100-100\sqrt{19}}{6}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+100\sqrt{19}}{2*3}=\frac{-100+100\sqrt{19}}{6}
$